g) A stream of water from a hose is sprayed horizontally on a wall at speed v =

Question

g) A stream of water from a hose is sprayed horizontally on a wall at speed v = 4.88 m/s. The hose carries 4.65 x10-4 m3 of water per second. (NOTE: The density of water is ? = 1000 kg/m3.) If the water hits the wall and falls straight down: find F, the magnitude of the force exeted by the water on the wall. N h) A moon of mass m = 2.71x1022 kg orbits a planet of mass M = 8.55x1024 kg in a circle of radius R = 5.97x105 km. Find Dcm, the distance from the center of the planet to the center of mass of the planet-moon system. km

Explanation / Answer

A hose with a nozzle 80mm in diameter ejects a horizontal stream of water at a rate of 0.044m^3s^-1? Calculate the mass of water leaving the nozzle each second (Density of water = 1000kgm^-3) and What will be the force exerted on a vertical wall situated close to the nozzle and at right angle to the stream of water if, after hitting the wall, the water falls vertically to the ground? 0.044 cubic metres of water leaves the nozzle in a second. 1 cubic metre of water has a mass of 1000 kg - so work out the mass of 0.044 kg. The force on the wall is the momentum change of the water in a second (force is rate of change of momentum (Newton's second law). You know the mass of the water hitting the wall - you need the velocity it leaves the hose at; each second a cylinder of water 80mm diameter and length equal to the velocity leaves the hose - you have just worked out the mass of this cylinder, so the only thing you need is the length (velocity). Having found the velocity of the water then Force = mass x velocity (initial momentum) - 0 (final momentum) So force on wall = mass of water x velocity of water. I would work this out for you but I'm tired, it's late!! good luck

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