A 1.20-kg ball, moving to the right at a velocity of +2.69 m/s on a frictionless

Question

A 1.20-kg ball, moving to the right at a velocity of +2.69 m/s on a frictionless table, collides head-on with a stationary 8.30-kg ball. Find the final velocities of (a) the 1.20-kg ball and of (b) the 8.30-kg ball if the collision is elastic. (c) Find the magnitude and direction of the final velocity of the two balls if the collision is completely inelastic.

Explanation / Answer

conservation of momentum it is. in first case the collision is elastic. m1u1 + m2u2 = m1v1 + m2v2 here m1 is moving ball, m2 is stationary => 1.2*2.69 + 8.3*0 = 1.2v1 + 8.3v2 -----------(1) we know that for elastic collision e =1 => v2 - v1 = u1 - u2 => v2 - v1 = 2.69 m/s -----------------(2) solving (1) & (2) we get (a) the final velocity of 1.20-kg ball v1 = -2.35 m/s that means to left (b) the final velocity of 8.30-kg ball v2 = +0.339 m/s that means to right (c) if the collision is inelastic. then m1u1 + m2u2 = (m1+m2)v where v is the combined final velocities of the two particles. => v = 0.339 m/s.

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