A 5.00-g bullet moving with an initial speed of v i = 390 m/s is fired into and

Question

A 5.00-g bullet moving with an initial speed ofvi=390m/s is fired into and passes through a 1.00-kg block as shown in the figure below. The block, initially at rest on a frictionless, horizontal surface, is connected to a spring with force constant880N/m. The block movesd=4.40cm to the right after impact before being brought to rest by the spring.

A 5.00 - g bullet moving with an initial speed ofvi=390m/s is fired into and passes through a 1.00 - kg block as shown in the figure below. The block, initially at rest on a frictionless, horizontal surface, is connected to a spring with force constant880N/m. The block movesd=4.40cm to the right after impact before being brought to rest by the spring. (a) Find the speed at which the bullet emerges from the block. (b) Find the amount of initial kinetic energy of the bullet that is converted into internal energy in bullet?block system during the collision.

Explanation / Answer

so .5*M*v^2=.5*k*x^2 so v(M)=1.305 so m*390=mv+M*v(M) so .005*390=.005*v+1*1.305 a)so v=129 m/s(ans) b)K=.5*m*390^2-.5*m*129^2-.5*1*1.305^2=337.8 J

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