A cross between population 1 and 2 results in the following distribution of phen
ID: 220034 • Letter: A
Question
A cross between population 1 and 2 results in the following distribution of phenotypes:
White eyed, long wings: 46.5%
Red eyed, short wings: 46.5%
White eyed, short wings: 3.5%
Red eyed, long wings: 3.5% 7% of the time there is a crossing over event
A cross between population 1 and 3 results in the following distribution of phenotypes:
White eyed, thin antennae: 47.5%
Red eyed, club antennae: 47.5%
White eyed, club antennae: 2.5%
Red eyed, thin antennae: 2.5%
A cross between population 1 and 4 results in the following distribution of phenotypes:
Long wings, thin antennae: 44%
Short wings, club antennae: 44%
Long wings, club antennae: 6%
Short wings, thin antennae: 6%
Using the information above, map the relative positions of the E, A, and W genes on the chromosome.
Remember to include relative genetic distances.
Group Worksheet 3 a- Search in Document Home Insert Design Layout References Mailings Review View tShare A Times New Ro… . | 12 , A? Av A?· Heading 1 StrengSubtle d. A cross between population 1 and 2 results in the following distribution of phenotypes: white eyed, long wings: 46.5% Red eyed, short wings: 46.5% white eyed, short wings: 3.5% Red eyed, long wings: 3.5% 7% of the time there is a crossing over event A cross between population 1 and 3 results in the following distribution of phenotypes: white eyed, thin antennae: 47.5% Red eyed, club antennae: 47.5% white eyed, club antennae: 2.5% Red eyed, thin antennae: 2.5% A cross between population 1 and 4 results in the following distribution of phenotypes: Long wings, thin antennae: 4496 Short wings, club antennae: 44% Long wings, club antennae: 6% Short wings, thin antennae: 6% Using the information above, map the relative positions of the E, A, and W genes on the chromosome. Remember to include relative genctic distances. Chromosome Page 3 of 4 1017 Words English (US) ???Focus 120%Explanation / Answer
E - Eye, W - Wings, A - Antennae
A cross between population 1 and 2 Eye and Wings
[(3.5 + 3.5)/100]X 100 = 7 cM
A cross between population 1 and 3 Eye and Antennae
[(2.5 + 2.5)/100]X 100 = 5 cM
A cross between population 1 and 3 Wings and Antennae
[(6 + 6)/100]X 100 = 12 cM
A----5cM---E-------7cM---W
--------------12cM----------------
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.