A 6.00 kg mass is traveling on a frictionless surface at a speed of 8.00 m/s. It

Question

A 6.00 kg mass is traveling on a frictionless surface at a speed of 8.00 m/s. It hits a 4.00 kg mass that was at rest and the two masses stick together. Find the amount of kinetic energy that was lost in the collision.

Explanation / Answer

Use Conservation of Momentum to find the resulting velocity. Then calculate the difference in Initial Kinetic Energy and Final... x-axis -> west east (west is negative) y-axis -> north south (south is negative) Calculate the p1 and p2 for EACH car (just by multiplying mv)... then you have the following equations: px: p2 = (m1 + m2)vx py: p1 = (m1 + m2)vy Calculate (vx, vy) the velocity of the two-car-system. Use this to calculate Kinetic energy: T = ½(m1 + m2)(vx² + vy²) For the Initial Kinetic Energy... T1 = ½(m1)(v1²), T2 = ½(m2)(v2²) Ttot = T1 + T2 ?T = T - Ttot

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