Jeff of the Jungle swings on a vine that is 7.20 m long (see the figure 1). At t

Question

Jeff of the Jungle swings on a vine that is 7.20 m long (see the figure 1). At the bottom of the swing, just before hitting the tree, Jeff's linear speed is 8.50 m/s . Suppose that at some point in his swing Jeff of the Jungle has an angular speed of 0.880 rad/s and an angular acceleration of 0.680 rad/s^2 (A) Find the magnitude of his centripetal acceleration (m/s^2). (B) Find the magnitude of his tangential acceleration (m/s^2). (C) Find the magnitude of his total acceleration (m/s^2). (D)Find the angle his total acceleration makes with respect to the tangential direction of motion (o).

Explanation / Answer

Direct answer --> 10.0 m/s^2 How to find it ... Use the equation: a = v^2/r Given values r = 7.20 m v = 8.50 m/s Centripetal acceleration a = (8.50 m/s)^2 / (7.20 m) a = (72.25 m^2/s^2) / (7.20 m) a = 10.0 m/s^2

Related Questions

Navigate

• Browse (All)
• Browse J
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.