(the drawing is not to scale) What is the potential energy stored in the spring
ID: 2203239 • Letter: #
Question
(the drawing is not to scale)What is the potential energy stored in the spring when it is compressed?3.86 J
What is the kinetic energy of the block just before it leaves the table but after it is no longer in contact with the spring?3.86 J
What is the kinetic energy of the block just before it hits the floor?
How much time elapses between the time when the block leaves the table and the time just before the block hits the floor?
What distance, d, from the edge of the table does the block hit the floor?
Explanation / Answer
potential energy stored in spring when compressed = (1/2) *K*x^2 =0.5*4.05*10^2*(1.38*10^-1)^2 =3.8 J Kinetic energy of block just before leaving is same as the potential energy of spring because the height of the block hasnt changed so the potential energy of the block hasnt changed.therefore the total kinetic energy of the block is due to the potential energy of the spring. therefore kinetic energy of block before leaving table=3.8 J Kinetic energy of block just before hitting the floor=potential energy of spring+potential energy of block which was stored in it due to its height therefore Kinetic energy of block just before hitting the floor =3.8+M*g*h =3.8+0.429*9.8*0.91 =3.8+3.82 =7.6 J Time elapsed between the time when the block leaves the table and the time just before the block hits the floor initial vertical velocity of block=0 therefore h=(1/2)*g*t^2 0.91=0.5*9.8*t^2 t^2=0.91/(0.5*9.8) t=0.43 s now initial horizontal velocity of block can be found kinetic energy = energy of spring=3.8 (1/2)*m*v^2=3.8 v^2=3.8/(0.5*0.215) v=5.9 m/s therefore distance d from edge of table where it falls(acceleration=0) =v*t =5.9*0.43 =2.53 m
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