A 2.5{\ m kg} ball and a 4.5{\ m kg} ball, each moving at 0.90 {\ m m}/{\ m s},

Question

A 2.5{ m kg} ball and a 4.5{ m kg} ball, each moving at 0.90 { m m}/{ m s}, undergo a head-on collision. The lighter ball rebounds opposite its initial direction, with speed 0.90 { m m}/{ m s}. Find the post-collision velocity of the heavier ball. Assume the initial direction of the lighter ball as positive. How much mechanical energy was lost in this collision? Express your answer in { m J}. How much mechanical energy was lost in this collision? Express your answer as a fraction of the system's initial mechanical energy.

Explanation / Answer

from momentum conservation: 2.5*.9 + 4.5*.9 = 2.5*.9 + 4.5*V so V will be .9 for heavier velocity also. no mechanical energy lost.

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