During the battle of Gettysburg, the two balls (bullets) had a head-on collision

Question

During the battle of Gettysburg, the two balls (bullets) had a head-on collision. The balls stopped and dropped to the ground - melted together. For this problem assume the balls are identical and traveling at same speed in opposite directions. During the collision all of their kinetice energy is converted to heat. Also assume that 40% of the mass of each ball is melted. The initial temperature is 30.0 degrees C. Find the speed of the balls just before the collision. You can use the following constants for lead: c=128 J/kgK Tmelt=328 degrees C Lf = 2.5x10^4 J/kg

Explanation / Answer

let velocity =v ke1=2(0.5*m*v^2)=m*v^2 ke1=0.4(2m)*[c*(328-30)+lf] v=224.75 m/s

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