A 15.0-kg block rests on a horizontal table and is attached to one end of a mass

Question

A 15.0-kg block rests on a horizontal table and is attached to one end of a massless, horizontal spring. By pulling horizontally on the other end of the spring, someone causes the block to accelerate uniformly and reach a speed of 5.00 m/s in 0.570 s. In the process, the spring is stretched by 0.220 m. The block is then pulled at a constant speed of 5.00 m/s, during which time the spring is stretched by only 0.0500 m. (a) Find the spring constant of the spring. N/m (b) Find the coefficient of kinetic friction between the block and the table.

Explanation / Answer

2) a = F/m ? (5/.5) = .05k/15 - µ*g and conservation of momentum gives 10*m = F*t ? 10*15 = (.05k - µg)*.5 Solve these 2 eqs for k & µ............

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.