Two plane mirrors stand facing each other, 3.01 m apart, and a woman stands betw

Question

Two plane mirrors stand facing each other, 3.01 m apart, and a woman stands between them. The woman faces one of the mirrors from a distance of 1.10 m and holds her left arm out to the side of her body with the back of her hand facing the closer mirror. (a) What is the apparent position of the closest image of her left hand, measured perpendicularly from the surface of the mirror in front of her? ? m behind the nearest mirror What is the position of the next closest image? m behind the nearest mirror What is the position of the third closest image? m behind the nearest mirror

Explanation / Answer

a) 1.3 m b) the other mirror makes its image at a position (3.23-1.3) behind it but this then treated as the object for the mirror in front of her position from front mirror is 3.23+(3.23-1.3) = 5.16 m c) the far mirror now uses the first image as its object so thats 3.23+1.3 away so this makes an image at 3.23*2+1.3 behind the rear mirror and this makes an image 3.23*3+1.3 behind the close mirror so 10.99 m

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