A 38 g block of ice is cooled to ?66?C. It is added to 547 g of water in an 91 g

Question

A 38 g block of ice is cooled to ?66?C. It is added to 547 g of water in an 91 g copper calorimeter at a temperature of 27?C. Find the ?nal temperature. The speci?c heat of copper is 387 J/kg

Explanation / Answer

Let the final temperature is t*C, =>By Q(lost) By water + Q(lost) by calorimeter = Q(gain) by ice =>ms(w)?t + ms(c)?t = ms(i)?t + mL(i) + ms(w)?t =>501 x 10^-3 x 4186 x (24-t) + 95 x 10^-3 x 387 x (24-t) = 34 x 10^-3 x 2090 x 80 + 34 x 10^-3 x 333000 + 34 x 10^-3 x 4186 x t =>50332464 - 2097186t + 882360 - 36765t = 5684800 + 11322000 + 142324t =>2276275t = 34208024 =>t = 15.03*C

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