spider silk has a young\'s modules of 4.0x10^9 n/m^2 and can withstand stresses

Question

spider silk has a young's modules of 4.0x10^9 n/m^2 and can withstand stresses up to 1.4x10^9 n/m^2. A single web strand has a cross-sectional area of 1.0x10^-11 m^2 and a web is made up of 50 radial strands. A bug lands in the center of a horizontal web so that the web stretches downward. A) If the maximum stress is exered on each strand, what angle Theta does the web make with the horizontal ? B) what does the mass of a bug have to be in order to exert this maximum stress on the web? C) if the web is .10 in radius, how far down does the web extend?

Explanation / Answer

F/A = 1.4x10^9 N/m^2 mg / A = 1.4x10^9 N/m^2 A = 50 strands * 1.0x10^-10 N/m^2 = 5.0x10^-10 so m = (1.4x10^9 N/m^2)(5.0x10^-10) / 9.8 m = 71.4g

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