In an amusement park ride called The Roundup, passengers stand inside a 19.0m -d

Question

In an amusement park ride called The Roundup, passengers stand inside a 19.0m -diameter rotating ring. After the ring has acquired sufficient speed, it tilts into a vertical plane, as shown in the figure .

In an amusement park ride called The Roundup, passengers stand inside a 19.0m -diameter rotating ring. After the ring has acquired sufficient speed, it tilts into a vertical plane, as shown in the figure . Suppose the ring rotates once every5.40s. If a rider's mass is58.0kg, with how much force does the ring push on her at the top of the ride?

Explanation / Answer

v=2pi*r/t = 11.05m/s At top of ride. Ftop=m*v^2/r - mg Ftop=177.5N

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