A water hose 2.95 cm in diameter is used by a gardener to fill a 34.0-liter buck

Question

A water hose 2.95 cm in diameter is used by a gardener to fill a 34.0-liter bucket. (One liter = 1,000 cm3.) The gardener notices that it takes 1.00 min to fill the bucket. A nozzle with an opening of cross-sectional area 0.500 cm2 is then attached to the hose. The nozzle is held so that water is projected horizontally from a point 1.00 m above the ground. Over what horizontal distance can the water be projected?

5.12 m CORRECT ANSWER

Use the values from PRACTICE IT to help you work this exercise. The nozzle is replaced with a Y-shaped fitting that splits the flow in half. Garden hoses are connected to each end of the Y, with each hose having a 0.390 cm2 nozzle. (a) How fast does the water come out of one of the nozzles?
m/s NEED ANSWER

(b) How far would one of the nozzles squirt water if both were operated simultaneously and held horizontally 1.00 m off the ground? (Hint: Find the volume flow rate through each 0.390-cm2 nozzle, then follow the same steps as before.)
m NEED ANSWER

Explanation / Answer

flow rate of water=34000cc/60s=566.67 cm3/s...area of nozzle=0.5 cm2...so velocity of water coming out from nozzle=566.67/0.5=1133.33 cm/s.=11.33 m/s...height from ground h=1m...initial vertical velocity=0....time taken to reach the ground=sqrt(2h/g)=sqrt(2/9.8)=0.45 s....so horizontal distance travelled=11.33*0.45=5.12 m.............in y shaped fitting flow rate through each nozzle=566.67/2=283.33 cm3/s....area of nozzle=0.39 cm2....So velocity of water coming out from nozzle=283.33/0.39=726.5 cm/s=7.26m/s.........(b)similarly as above time taken for the water to hit ground=0.45s.....so horizontal distance travelled=7.26*0.45=3.27 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.