A bullet of mass m1 is fired horizontally at a speed vo into a wooden block of m

Question

A bullet of mass m1 is fired horizontally at a speed vo into a wooden block of mass M2. The bul- let instantaneously comes to rest in the block. The block with the embedded bullet slides a dis- tance s along a horizontal surface with a coefficient of kinetic friction ?. Which one of the fol- lowing expressions determines how far (s) the block slides before it comes to rest.

Explanation / Answer

here............conservation of momentum is applied:...m1vo = (m1+M2)Vi...Vi = m1vo /(m1+M2).... now, it stops at "s" distance,,,,,,so,=> a = V^2i / 2s = [m1vo /(m1+M2)]^2 / 2s......frictional force = umg...=> umg= ma...a = ug............=>ug =[m1vo /(m1+M2)]^2 / 2s => s = [m1vo /(m1+M2)]^2 / 2ug......answer....( u = kinetic frictional coeff)..........

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