A sports car weighing 500 kg and traveling at 27 m/s fails to stop at an interse
ID: 2211914 • Letter: A
Question
A sports car weighing 500 kg and traveling at 27 m/s fails to stop at an intersection and crashes into a 1600 kg delivery truck traveling at 20 m/s in a direction at right angles to it. The wreckage becomes locked and travels 18 m before coming to rest. Find the coefficient of kinetic friction between the road and the car + truck system during the sliding-to-rest stage.I know the answer is 0.77, but I don't know how to get there. Can someone please show me step by step? I also already know that the initial velocitity of the car+truck as they start the slide is <6.49,15.2>m/s.
Explanation / Answer
As we know
Work Done by Friction = Change in Kinetic Energy
µMgs = 0.5*MV^2
V = sqrt(6.49^2+15.2^2)
= 16.527
Therefore , we get
µ = (0.5*16.527^2)/(9.8*18)
= 0.77
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