The graph shows the US Department of Labor noise regulation for working without
ID: 2213558 • Letter: T
Question
The graph shows the US Department of Labor noise regulation for working without ear protection. A machinist is in an environment where the ambient sound level is of 85 dB, i.e., corresponding to the 8 Hours/day noise level. The machinist likes to listen to music, and plays a Boom Box at an average level of 88.0 dB.
Calculate the INCREASE in the sound level from the ambient work environment level (in dB). Compute the intensities from the levels, add them to get the total intensity, then find the total sound level. Note the question asks for the increase.
A student at a rock concert has a seat close to the speaker system, where the average sound intensity corresponds to a sound level of 114 dB. By what factor does that sound intensity exceed the 1.5- Hours/day intensity limits from the graph?
The graph shows the US Department of Labor noise regulation for working without ear protection. A machinist is in an environment where the ambient sound level is of 85 dB, i.e., corresponding to the 8 Hours/day noise level. The machinist likes to listen to music, and plays a Boom Box at an average level of 88.0 dB. Calculate the INCREASE in the sound level from the ambient work environment level (in dB). Compute the intensities from the levels, add them to get the total intensity, then find the total sound level. Note the question asks for the increase. A student at a rock concert has a seat close to the speaker system, where the average sound intensity corresponds to a sound level of 114 dB. By what factor does that sound intensity exceed the 1.5- Hours/day intensity limits from the graph?Explanation / Answer
The graph shows the US Department of Labor noise regulation for working without ear protection. A machinist is in an environment where the ambient sound level is of 85 dB, i.e., corresponding to the 8 Hours/day noise level. The machinist likes to listen to music, and plays a Boom Box at an average level of 86.0 dB. a) Calculate the INCREASE in the sound level from the ambient work environment level (in dB). b) A student at a rock concert has a seat close to the speaker system, where the average sound intensity corresponds to a sound level of 118 dB. By what factor does that sound intensity exceed the 1- Hours/day intensity limits from the graph? Heres part a): turn the dB levels in powers of 10. To do this simply divide the dB level by 10. 85 = 10^(8.5) 86 = 10^(8.6) 10log(10^(8.5) + 10^(8.6)) = 88.539 dB 88.539 - 85 = 3.539 dB 3.54 rounded (2dp)
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