a frictionless roller car of mass M tops the first hill with a speed of (V0)m/s

Question

a frictionless roller car of mass M tops the first hill with a speed of (V0)m/s at height h. In terms of h and (V0), how much work does the gravitational force do on the car from that point to: a) point A? b) point B? c) Point C? In the gravitational potential energy of the car-Earth system is taken to be zero at point C, what is the value of PE when the car is at: d) Point B? e) Point A? If the mass M were doubled, would the change in the gravitational PE of the system between Points A and B f) incease, decrease or remain the same?

Explanation / Answer

change in potential energy = mgh since there is no friction so , P.E =K.E (may this be helpful to you :) )

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