At perihelion (closest approach to the Sun), Earth is 1.47 * 108 km from the Sun
ID: 2218733 • Letter: A
Question
At perihelion (closest approach to the Sun), Earth is 1.47 * 108 km from the Sun and its orbital speed is 30.3 km/s. What is Earths orbital speed at aphelion (greatest distance from the Sun), when it is 1.52 * 108 km from the Sun? Note that at these two points Earths velocity is perpendicular to a radial line from the Sun
Explanation / Answer
Conservation of angular momentum about center of rotation: r=perihilion R=aphelion M*V*R=M*v*r V=v*r/R V=29.3km/s
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.