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A steady stream of 0.450 kg snowballs is shot perpendicularly into a wall at a s

ID: 2218960 • Letter: A

Question

A steady stream of 0.450 kg snowballs is shot perpendicularly into a wall at a speed of 6. 50 m/s. Each ball sticks to the wall. The figure gives the magnitude F of the force on the wall as a function of time t for two of the snowball impacts. Impacts occur with a repetition time interval Delta tr = 50. 0 ms, last a duration time interval Delta td = 10 ms, and produce isosceles triangles on the graphm eith each impact reaching a force maximum Fmax = 585 N. What is the magnitude of the impulse on the wall during each impact? N-s What is the magnitude of the average force on the wall during each impact? N During a time interval of many impacts, what is the magnitude of the average force on the wall? N

Explanation / Answer

Impulse = Force*time


Here


Impulse = Area of the Triangle


= 0.5*585*10*10^-3


=2.925 N.sec


=============================


Average Force = Impuse/time


= 2.925/(10*10^-3)


=292.5 N


=================

Average Force remains same as average Force of each Impact is same


= 292.5 N

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