can you please explain both of these questions to me 1) you have a DNA detection
ID: 222000 • Letter: C
Question
can you please explain both of these questions to me
1) you have a DNA detection technique which allows you to visualize 10 nanograms of DNA. you know that the average molecular weight of a basepair is 660gm/mole. if a gene is exactly 4,000 basepair long, and is present only once in a bacterial genome ( 4 million basepairs), how many ugs of bacterial genomic DNA do you have to load onto the gel to be able to visualize the hybirdized DNA band?
2) you have a DNA detection technique which allows you to visualize 10 nanograms of DNA. you know that the average molecular weight of a basepair is 660gm/mole. if a gene is exactly 4,000 basepair long, and is present only once in a bacterial genome ( 4 million basepairs), how many DNA fragments of this gene do you need to have present to detect (those 10ng) of the gene-specific DNA fragment?
Explanation / Answer
1. if we compare your gene with the genome of the organism we will find that the gene is made up of 0.1% of total genome
4000/4000000 = 1/1000 = 0.1%
So if we load 1µg of genomic DNA then we will be able to visualise the DNA hybrid.
2. total Mw of gene will be 4000*2*660
4000= number of nucleotide in one strand and DNA has two strands so we need to multiply 4000*2
Mw = 5280000 gm
5280000 contains 6.023*1023 molecules of DNA
So 10 ng of DNA contain X number of molecules
5280000/10*10-9 = 6.023*1023/x
X = 6.023*1023*10*10-9/5280000
=* 1.14*109 molecules
1gm = 109 ng
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