A spring of stiffness 127 N/m, and with relaxed length 0.22 m, stands vertically

Question

A spring of stiffness 127 N/m, and with relaxed length 0.22 m, stands vertically on a table, as shown in the figure. Instead of compressing the spring with a heavy block, with your hand you push straight down on the spring until your hand is only 0.19 m above the table. (Assume that the positive y-axis points upward and is normal to the table.) What is now the vector L rightarrow , with the spring compressed? What is the magnitude of |L|? |L| rightarrow = m What is the unit vector L? L = What is the stretch, s, including the correct sign? s = m What is the force F rightarrow exerted on your hand by the spring? F rightarrow = N

Explanation / Answer

F=kx=127*0.03 j=3.81j N

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