A mortar* crew is positioned near the top of a steep hill. Enemy forces are char

Question

A mortar* crew is positioned near the top of a steep hill. Enemy forces are charging up the hill and it is necessary for the crew to spring into action. Angling the mortar at an angle of ? = 61.0o (as shown), the crew fires the shell at a muzzle velocity of 249 feet per second. How far down the hill does the shell strike if the hill subtends an angle ? = 36.0o from the horizontal? (Ignore air friction.) a)How long will the mortar shell remain in the air? b)How fast will the shell be traveling when it hits the ground?

Explanation / Answer

where is the figure can you plz upload it so that i can solve it or you can rate me as this is the only way i can earn karma points...

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.