The figure below shows a graph of vx versus t for the motion of a motorcyclist a

Question

The figure below shows a graph of vx versus t for the motion of a motorcyclist as he starts from rest and moves along the road in a straight line. (a) Find the average acceleration for the time interval t = 0 to t = 10.0 s. m/s2 (b) Estimate the time at which the acceleration has its greatest positive value. s What is the value of the acceleration at that instant? m/s2 (c) When is the acceleration zero? Acceleration is zero when t = The correct answer is not zero. s and when t > s. (d) Estimate the maximum negative value of the acceleration. m/s2 At what time does it occur? s

Explanation / Answer

consider intial velocity at t = 0 adn final velocity at t = 6sec plugging thevalues we can solve for acceleration. b)the greatest value of accleration willbe at the point where the tangent drawn to the curuve makes largestangle with X- axis i.e at t = 3sec c)acceleration is = 0 at the pointof time where the tangent drawn to the curve is parellel to time-axis i.e at t= 6 sec d) maximum negative acceleration is thepoint on the time axis where the tangent drawn tothe cureve makes maximum negative angle with horizantalaxis i.e at t =7 sec accelration at a point of time ,t a = dv / dt = tan? , ? is the angle made by thesurve at time , t

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