In the figure a nonconducting rod of length L = 8.22 cm has charge -q = -4.48 fC

Question

In the figure a nonconducting rod of length L = 8.22 cm has charge -q = -4.48 fC uniformly distributed along its length. (a) What is the linear charge density of the rod? What are the (b) magnitude and (c) direction (positive angle relative to the positive direction of the x axis) of the electric field produced at point P, at distance a = 12.9 cm from the rod? What is the electric field magnitude produced at distance a = 78 m by (d) the rod and (e) a particle of charge -q = -4.48 fC that replaces the rod?

Explanation / Answer

a:s=-4.48/8.22 fc/cm; b:1/4pie0[integral ofsdx/(x+a) from x=0 to x=L] where a=12; c:direction would be in the direction of axis of the rod and towards the rod; d-SAME Above formule will be used with a=78m; e-position of that charge is to be mentioned else can not be found

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