Two small, identical particles have charges Q1 = +7.5 ?C and Q2 = -19?C. The par

Question

Two small, identical particles have charges Q1 = +7.5 ?C and Q2 = -19?C. The particles are conducting and are brought together so that they touch. Charge then moves between the two particles so as to make the excess charge on the two particles equal. If the particles are then separated by a distance of 65 mm, what is the magnitude of the electric force between them? I tried using F = K*(Q1*Q2/R^2) but this does not work and I don't understand why. I'm looking for help on understanding this concept and how to solve it.

Explanation / Answer

so after they touch they will equalize their charge to a new q q = (q1 + q2)/2 = (7.5-19)/2= -5.75 uC F = kq^2/r^2 = 9*E9 *5.75*E-6^2/(65*E-3)^2 = 70.43 N

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