In a rectangular coordinate system, a positive point charge q = 4.50 nC (4.50E-9

Question

In a rectangular coordinate system, a positive point charge q = 4.50 nC (4.50E-9 C) is placed at the point x = 0.180m, y = 0, and a identical point charge is placed at x = - 0.18m, y = 0. Find the x and y components and the magnitude and direction of the electric field at the following points.

A) Find the x and y components and the magnitude and direction of the electric field at x = 0.180 m and y = - 0.350 m.

B) Find the total electric field.

C) Find?.

Thank you!!

Explanation / Answer

q1=4.5 nC q2=4.5 nC P(0.18,-0.35) At P, Electric field due to q1 =(k x q1)/r^2 =9 x 4.5/0.35^2 =330.6122 N/C ........(1) in negative y axis Electric field due to q2 =kq1/r^2 =9 x 4.5/(0.35^2 + 0.18^2) =261.459 N/C ........(2) it makes angle ? with -y axis such that, tan? = 0.18/0.35 => ? = 0.475 a) x component of E= E2 sin? = 261.459 sin(0.475)=119.57 N/C y component of E= E1 + E2 cos? = 330.6122+261.459 cos(0.475)=563.1257 N/C b) total E = (119.57^2+563.1257^2)^1/2=575.6800 N/C

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