In a rectangular coordinate system, a positive point charge q = 4.50 nC is place

Question

In a rectangular coordinate system, a positive point charge q =                    4.50 nC is placed at the point x= 0.210                    m, y=0, and an identical point charge is placed at x = -0.210 m, y=0.

Ex=____N/C     Ey=____N/C     E=____N/C      theta=____degrees

In a rectangular coordinate system, a positive point charge q = 4.50 nC is placed at the point x= 0.210 m, y=0, and an identical point charge is placed at x = -0.210 m, y=0. Find the x m fdguk cd x and y components and the magnitude and direction of the electric field at x = 0.210m, y = -0.450m

Explanation / Answer

A) at x= 0.21 m....and y=-0.45m.........

Ex=[k*Q/0.615^2]*cos?.....

cos?=0.42/sqrt[0.42^2+0.45^2]....

cos?=0.42/0.615=0.682.....

Ex=73.027 N/C.....

Ey=[k.Q/(0.45^2)] +[k*Q/0.615^2]*sin?.....

sin?=0.45/0.615=0.731

Ey=200+78.274=278.274 N/C

it is in negative Y-direction

so Ey=-278.274 N/C

angle tan?=Ey/Ex=-75.3 below the -X-axis

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