Three negative point charges lie along a line as shown in the figure. Find the m

Question

Three negative point charges lie along a line as shown in the figure. Find the magnitude and direction of the electric field this combination of charges produces at point P, which lies 6.00 cm (0.06 m) from the - q2 charge measured perpendicular to the line connecting the three charges. Assume q1 = 5.05 uC (5.05E-6 C) and q2 = 2.05 uC (2.05E-6 C). E = ___ N/C ?

Explanation / Answer

Distance betn q1 & P = 10 cm Angle theta= arctan(8/6) = 53.13 y- axis components wl cancel due to opposite dirn & equal magnitude Net Electric Field due to q1 upper & lower charges,Enet = 2*k*q1*cos(theta)/(10cm^2) =>5454012.991 N/C (towards left) Electric field due to q2,E2 = k*q2/(6cm^2) = 5125000 N/C (towards left) Etotal = E2 + Enet = 5125000 N/C (towards left) + 5454012.991 N/C (towards left) =>10579012.99 N/C (towards left) =>1.06*10^7 N/C

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.