An object is launched from a known height at a known speed and a known angle abo

Question

An object is launched from a known height at a known speed and a known angle above the horizontal. Which single equation allows you to find the vertical component of its velocity vector just before it hits the ground? = xo + vox t + 1/2 ax t2 vx = vox + ax t vx2 = vox2 + 2 ax (x-xo) y = yo + voy t + 1/2 ay t2 vy = voy + ay t vy2 = voy2 + 2 ay (y-yo) An object is launched at a known speed and a known angle above the horizontal. Which single equation allows you to find the maximum height of its trajectory? x = xo + vox t + 1/2 ax t2 vx = vox + ax t vx2 = vox2 + 2 ax (x-xo) y = yo + voy t + 1/2 ay t2 vy = voy + ay t vy2 = voy2 + 2 ay (y-yo)

Explanation / Answer

x = x0 + vox t + 1/2 ax t2 and y = y0 + voy t + 1/2 ay t2 will be helpful in 1st problem. vy = voy + ayt. As at highest point vy = 0, and others are known, we can find out t. The equations needed are: y = y0 + v0y t + 1/2 ay t2 and vy = v0y + ayt

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