Eddie the Eagle, British Olympic ski jumper, is attempting his most mediocre jum

Question

Eddie the Eagle, British Olympic ski jumper, is attempting his most mediocre jump yet. After leaving the end of the ski ramp, he lands downhill at a point that is displaced 64.3 m horizontally from the edge of the ramp. His velocity just before landing is 29.0 m/s and points in a direction 34.0$^circ$ below the horizontal. Neglect any effects due to air resistance or lift. a-What was the magnitude of Eddie's initial velocity as he left the ramp? b-Determine Eddie's initial direction of motion as he left the ramp, measured relative to the horizontal. c-Calculate the height of the ramp's edge relative to where Eddie landed.

Explanation / Answer

a-What was the magnitude of Eddie's initial velocity as he left the ramp?

t = x/vx = 64.3/(29*cos34) = 2.6745 s

vyi = vyf - g t = (-29*sin34) + 9.8 * 2.6745 = 9.9935 m/s

v = (9.9935*9.9935+24.04*24.04) = 26.034

==> v = 26.0 m/s

b-Determine Eddie's initial direction of motion as he left the ramp, measured relative to the horizontal.

= Arctan(9.9935/24.04) = 22.6 degrees

c-Calculate the height of the ramp's edge relative to where Eddie landed.

h = 0.5 gt^2+v0 t = 0.5*(-9.8)*2.6745*2.6745 + 9.9935*2.6745

==> h = 8.32 m

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