A bicycle is turned upside down while its owner repairs a flat tire. A friend sp

Question

A bicycle is turned upside down while its owner repairs a flat tire. A friend spins the other wheel of radius .4 m and observes that drops of water fly off tangentially. She measures the height reached by drops moving vertically. A drop that breaks loose on the next turn rises 37.5 cm above the tangent point. A drop that breaks loose on the next turn rises 34.1 cm above the tangent point (the angular speed of the wheel is decreasing). Find the angular deceleration of the wheel. The acceleration due to gravity is 9.8 m/s^2. Assume the angular deceleration is constant. Answer in units of rad/s^2.

Explanation / Answer

0.3314 rad/s^2 u = sqrt(2gh1) v = sqrt(2gh2) wf^2 = wi^2 + 2*(ang acceleration)*(angle rotated in radians) use w = v/r and angle rotated is 2*pi radians

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