2. -6 points My Notes I M13 3.13 X.024 You and a friend each hold a lump of wet

Question

2. -6 points My Notes I M13 3.13 X.024 You and a friend each hold a lump of wet clay. Each lump has a mass of 35 grams. You each toss your lump of clay into the air, where the lumps collide and stick together. Just before the impact, the velocity of one lump was 3, 3, -3 m/s, and the velocity of the other lump was 2, 0, -4 m/s. What was the the total momentum of the lumps just before the impact? kg m/s ptotal What is the momentum of the stuck-together lump just after the collision? kg m/s What is the velocity of the stuck-together lump just after the collision? m/s Submit Answer Save Progress

Explanation / Answer

in this question, the momentum is conserved, so , for the x direction, 0.035*3+0.035*(-2)=0.07*v or v=0.5 for the y direction, 0.035*3+0.035*0=0.07*v or v=1.5 m/s for the z direction, 0.035*(-3)+0.035*(-4)=0.07v or v=-3.5 m/s so velocity momentum is = according to law of conservation of momentum, momentum of the stick together mass=

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