Find the equivalent single capacitance of the two capacitors in series and redra

Question

Find the equivalent single capacitance of the two capacitors in series and redraw the diagram (called diagram 1) with this equivalent capacitance. In diagram 1 find the equivalent capacitance of the three capacitors in parallel and redraw the diagram as a single battery and single capacitor in a loop. Compute the charge on the single equivalent capacitor. Returning to diagram 1, compute the charge on each individual capacitor. 4.0- mu F capacitor 0.500- mu F capacitor 23.0- mu F and 8.00- mu F equivalent capacitor Does the sum agree with the value found in part (c)? Yes No What is the charge on the 23.0- mu F capacitor and on the 8- mu F capacitor? Compute the voltage drop across the 23.0- mu F capacitor. Compute the voltage drop across the 0.500- mu F capacitor.

Explanation / Answer

Can you tell me the values of C1 and C2 ... You rate this I will give you a good explanaition :)

Thank you!

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