show steps please! The figure below shows an overhead view of a lemon half and t
ID: 2236693 • Letter: S
Question
show steps please!
The figure below shows an overhead view of a lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force has a magnitude of 5.90 N and is at theta = 26.degree Force has a magnitude of 7.00 N and is at theta 2 = 26 degree . The lemon half has mass 0.0200 kg. What is the third force if the lemon half has zero velocity? What is the third force if the lemon half has constant velocity? What is the third force if the lemon half has a varying velocity? m/s, where t is time in secondsExplanation / Answer
a) if zero velocity :
F1 + F2 + F3 = 0
- 5.90cos26i + 5.90sin26j + 7sin26i - 7cos26j + F3= 0
F3 = -2.23i - 3.70j ....Ans
|F3| = sqrt(2.23^2 + 3.70^2) = 4.32 N
angle = tan^-1(3.70/2.23) = 58.92 degrees below from -ve x-axis.
b) its same case as discussed in part a)
F3 = -2.23i - 3.70j ....Ans
|F3| = sqrt(2.23^2 + 3.70^2) = 4.32 N
angle = tan^-1(3.70/2.23) = 58.92 degrees below from -ve x-axis.
c) dv/dt = Fnet / m
13i + 14j = (2.23i + 3.70j + F3)/0.02
2.23i + 3.70j + F3 = 0.26i + 0.28j
F3 = - 1.97i - 3.42j N
|F3| = sqrt(1.97^2 + 3.42^2) = 3.95 N
angle = tan^-1(3.42/1.97) = 60.05 degrees below from -ve x-axis.
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