A block of mass 10 kg is dropped from a height of 50 cm onto a spring of spring

Question

A block of mass 10 kg is dropped from a height of 50 cm onto a spring of spring constant k = 1500 N/m. What is the distance the spring is compressed? A block of mass 4 kg slides from rest a distance d down a frictionless incline at an angle of 30 degrees where it runs into a spring of spring constant 400 N/m. When the block momentarily stops, it has compressed the spring by 20 cm. What are (a) distance d and (b) the distance between the point of the first block-spring contact and the point where the block's speed is greatest?

Explanation / Answer

mgh=0.5*k*x^2 x^2=10*9.8*0.5/(0.5*1500). x=0.2556m b)4*9.8*x*sin30=0.5*400*0.2*0.2 x=0.408m

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