Yellow light is incident on a metal photocathode and a current is measured in th

Question

Yellow light is incident on a metal photocathode and a current is measured in the attached ammeter. If instead green light of the same POWER is used, what happens to the (i) kinetic energy of the emitted electrons and the (ii) current measured in the ammeter?

(i) increases (ii) decreases

(i) no change, (ii) decreases

(i) increases, (ii) no change (i) decreases, (ii) no change (i) no change, (ii) increases

(i) increases (ii) decreases

(i) no change, (ii) decreases

(i) increases, (ii) increases (i) decrease, (ii) increase

Explanation / Answer

same power = no.of photons of green light is less than that of yellow

So, no.of elctrons emitted decreases = current decreases.

Kinetic energy increases because total energy- Work function is more for green than yellow light.

So, (i)= increases

(ii)= decreases

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