Find the x and y components and the magnitude and direction of the electric fiel

Question

Find the x and y components and the magnitude and direction of the electric field at x=0.420 m, y=0.      Ex=____N/C      Ey=____N/C    E=____N/C In a rectangular coordinate system, a positive point charge q = 4.50 is placed at the point x= 0.210 m, y=0, and an identical point charge is placed at x = -0.210 m, y=0. Find the x and y components and the magnitude and direction of the electric field at the following points. Find the x and y components and the magnitude and direction of the electric field at x = 0.420 m, y = 0.

Explanation / Answer

Electric field due to the +ive charge=k*q/r^2 in the radial direction or along the line joing the point and the charge away from the charge

=> E(0.420,0)=(k*q/r1^2+k*q/r2^2)i i.e alonf +ive x

where r1=0.21m r2=0.63m

=> E=9*10^9*4.5*10^-9 (1/0.21^2 + 1/0.63^2)   

E=1020.38 N/C along +ive x

=>Ex=__1020.38 N/C__N/C Ey=_ 0___N/C E=__1020.38 N/C__N/C

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