At the instant of Figure 11-39, a 1.2 kg particle P has a position vector r of m

Question

At the instant of Figure 11-39, a 1.2 kg particle P has a position vector r of magnitude 2.7 m and angle ?1 = 45

At the instant of Figure 11-39, a 1.2 kg particle P has a position vector r of magnitude 2.7 m and angle ?1 = 45 degree and a velocity vector v of magnitude 3.5 m/s and angle ?2 = 30 degree. Force F of magnitude 2.7 N and angle ?3 = 30 degree acts on P. All three vectors lie in the xy plane. What is the angular momentum of the particle about the origin? What is the torque acting on the particle about the origin?

Explanation / Answer

plzzraise the points .. i will help you..its too lengthy for 300pts

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