A square wire loop with 2.00 m sides is perpendicular to a uniform magnetic fiel

Question

A square wire loop with 2.00 m sides is perpendicular to a uniform magnetic field, with half the area of the loop in the field as shown in the figure below. The loop contains an ideal 20.0 V battery. The magnitude of the field varies with time according to B = 0.4570 - 0.940t, with B in teslas and t in seconds.

A square wire loop with 2.00 m sides is perpendicular to a uniform magnetic field, with half the area of the loop in the field as shown in the figure below. The loop contains an ideal 20.0 V battery. The magnitude of the field varies with time according to B = 0.4570 - 0.940t, with B in teslas and t in seconds. What is the net emf in the circuit? What is the direction of the (net) current around the loop?

Explanation / Answer

Area

A =(1/2)L^2= (1/2)*2^2 =2m^2

dB/dt =-0.94 T/s

E=-NA(dB/dt)

E=-1*2*(-0.94)

E=1.88 V

Net emf is

E_net=1.88+20

E_net =21.88 V

b)

counterclock wise

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