An object of height 0.1m is located 2m in front of a convex lens of focal length

Question

                                                              An object of height 0.1m is located 2m in front of a                                                                   convex lens of focal length of |f| = 0.5m A second                                                                   convex lens of focal length |f| = 0.2m is located a                                                                   distance L to the right of the first lens. The final image                                                                   made by the second lens is 0.2m high and upright.                                                                   (The net effect of the two lenses is to magnify the                                                                   initial object by +2.)                                                                   a. Find the position of the image made by the first lens.                                                                   b. What does the magnification of the second lens have to be?                                                                   c. Find L.                                                                                                                  An object of height 0.1m is located 2m in front of a                                                                   convex lens of focal length of |f| = 0.5m A second                                                                   convex lens of focal length |f| = 0.2m is located a                                                                   distance L to the right of the first lens. The final image                                                                   made by the second lens is 0.2m high and upright.                                                                   (The net effect of the two lenses is to magnify the                                                                   initial object by +2.)                                                                   a. Find the position of the image made by the first lens.                                                                   b. What does the magnification of the second lens have to be?                                                                   c. Find L.                                                                                                 An object of height 0.1m is located 2m in front of a                                                                   convex lens of focal length of |f| = 0.5m A second                                                                   convex lens of focal length |f| = 0.2m is located a                                                                   distance L to the right of the first lens. The final image                                                                   made by the second lens is 0.2m high and upright.                                                                   (The net effect of the two lenses is to magnify the                                                                   initial object by +2.)                                                                   a. Find the position of the image made by the first lens.                                                                   b. What does the magnification of the second lens have to be?                                                                   c. Find L.                                                               An object of height 0.1m is located 2m in front of a                                              convex lens of focal length of |f| = 0.5m A second                                              convex lens of focal length |f| = 0.2m is located a                                              distance L to the right of the first lens. The final image                                              made by the second lens is 0.2m high and upright.                                              (The net effect of the two lenses is to magnify the                                              initial object by +2.)                                              a. Find the position of the image made by the first lens.                                              b. What does the magnification of the second lens have to be?                                              c. Find L.                     

Explanation / Answer

a) 1/2 + 1/S1' = 1/0.5

S1' = 0.67 m

m1 = -S1'/S1 = 0.67/2 = -0.335

b) M = m1*m2 = 2

m2 = 2/m1 = -2/.335 = -5.9701

c)m2 = S2'/S2 ===> S2' = S2*m2 = -5.9701*S2

1/S2 + 1/S2' = 1/f2

1/S2 - 1/5.9701*S2 = 1/0.2

S2 = 0.1665 m

L = S1'+S2 = 0.8365 m

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