What is the angular position ? of the second-order bright fringe in a double-sli

Question

What is the angular position ? of the second-order bright fringe in a double-slit system with 1.9?m slit spacing if the light has wavelength Part A 405nm ?   ?1 =   ?   SubmitMy AnswersGive Up Try Again; 4 attempts remaining Part B 715nm ?   ?2 =   ?   SubmitMy AnswersGive Up What is the angular position ? of the second-order bright fringe in a double-slit system with 1.9?m slit spacing if the light has wavelength What is the angular position ? of the second-order bright fringe in a double-slit system with 1.9?m slit spacing if the light has wavelength What is the angular position ? of the second-order bright fringe in a double-slit system with 1.9?m slit spacing if the light has wavelength What is the angular position ? of the second-order bright fringe in a double-slit system with 1.9?m slit spacing if the light has wavelength Part A 405nm ?   ?1 =   ?   SubmitMy AnswersGive Up Try Again; 4 attempts remaining Part B 715nm ?   ?2 =   ?   SubmitMy AnswersGive Up Part A 405nm ?   ?1 =   ?   SubmitMy AnswersGive Up Try Again; 4 attempts remaining Part B 715nm ?   ?2 =   ?   SubmitMy AnswersGive Up Part A 405nm ?   ?1 =   ?   SubmitMy AnswersGive Up Try Again; 4 attempts remaining Part B 715nm ?   ?2 =   ?   SubmitMy AnswersGive Up Part A 405nm ?   ?1 =   ?   SubmitMy AnswersGive Up Try Again; 4 attempts remaining Part B 715nm ?   ?2 =   ?   SubmitMy AnswersGive Up Part A 405nm ?   ?1 =   ?   SubmitMy AnswersGive Up Try Again; 4 attempts remaining Part A 405nm ?   ?1 =   ?   SubmitMy AnswersGive Up Try Again; 4 attempts remaining   ?1 =   ?     ?1 =   ?   SubmitMy AnswersGive Up Try Again; 4 attempts remaining Try Again; 4 attempts remaining Try Again; 4 attempts remaining Part B 715nm ?   ?2 =   ?   SubmitMy AnswersGive Up Part B 715nm ?   ?2 =   ?   SubmitMy AnswersGive Up   ?2 =   ?     ?2 =   ?   SubmitMy AnswersGive Up What is the angular position ? of the second-order bright fringe in a double-slit system with 1.9?m slit spacing if the light has wavelength Part A 405nm ?   ?1 =   ?   SubmitMy AnswersGive Up Try Again; 4 attempts remaining Part B 715nm ?   ?2 =   ?   SubmitMy AnswersGive Up

Explanation / Answer

The angle 'theta' for the interference maximum in Young's double-slit experiment is given by the

sin(theta)=(n X lamda) /d

where lamda = wavelength

and d= slight spacing = 1.9 um = 1.9 X 10^-6 m

n= order of bright fringe= 2

AT lamda= 405 nm = 405 X 10^-9 m

sin theta = (2X405 X 10^-9)/1.9 X 10^-6

theta = 25.234 degrees...ANSWER

AT lamda= 715 nm = 715 X 10^-9 m

sin theta = (2X715 X 10^-9)/1.9 X 10^-6

theta = 48.82 degrees...ANSWER

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