In the figure, a light ray enters a glass slab at point A at incident angle ? 1

Question

In the figure, a light ray enters a glass slab at point A at incident angle ?1 = 65.7o and then undergoes total internal reflection at point B. What minimum value for the index of refraction of the glass can be inferred from this information? Assume that the index of refraction of air under standard temperature (0

In the figure, a light ray enters a glass slab at point A at incident angle ?1 = 65.7 degree and then undergoes total internal reflection at point B. What minimum value for the index of refraction of the glass can be inferred from this information? Assume that the index of refraction of air under standard temperature (0 degree C) and pressure (1 atm) is 1.00029.

Explanation / Answer

n2sintheta2/n2costheta2 = sintheta1/costheta1

tan theta2 = sin 65.7/1

tan theta2 = sin65.7

theta2 = arctan(sin65.7)

theta = 42.34 degrees

sin65.7/sin42.34 = n2 = 1.353

n2 = 1.353

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