Determine the mass defect (in u) for (a) helium-3 ( 2 He 3 ), which has an atomi

Question

Determine the mass defect (in u) for (a) helium-3 (2He3), which has an atomic mass of 3.016 030 u, and (b) the isotope of hydrogen known as tritium (1T3), which has an atomic mass of 3.016 050 u.(c) On the basis of your answers to parts (a) and (b), state which nucleus requires more energy to disassemble it into its separate and stationary constituent nucleons.

Determine the mass defect (in u) for (a) helium-3 (2He3), which has an atomic mass of 3.016 030 u, and (b) the isotope of hydrogen known as tritium (1T3), which has an atomic mass of 3.016 050 u. (c) On the basis of your answers to parts (a) and (b), state which nucleus requires more energy to disassemble it into its separate and stationary constituent nucleons.

Explanation / Answer

The helium 3/2 He nucleus has two protons
so 3 - 2 = 1 neutron
a) mass defect : delta m = 2(1.007825 u) + 1(1.008665 u) - 3.016030 u
=0.008285 u
--------------------------------------------------- The tritium 3/1 T nucleus has 1 proton
so 3-1 = 2 neutrons
delta m = 1(1.007825 u) + 2(1.008665 u)- 3.016050 u
= 0.009105 u
---------------------------------------------------
c) The mass defect for tritium 3/1 T is greater than helium 3/2 He.
Bindingenergy = (Mass defect)c^2 = (deltam)c^2
More energy should be supplied totritium 3/1 T than to helium 3/2 He. c) The mass defect for tritium 3/1 T is greater than helium 3/2 He.
Bindingenergy = (Mass defect)c^2 = (deltam)c^2
More energy should be supplied totritium 3/1 T than to helium 3/2 He.

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