A small helium-neon laser emits red visible light with a power of 3.85 mW in a b
ID: 2246265 • Letter: A
Question
A small helium-neon laser emits red visible light with a power of 3.85 mW in a beam that has a diameter of 2.80 mm.
Explanation / Answer
I have solved this question earlier with different figures. Please workout using yours figures. If you need any further help just PM me. If I have helped you please rate me 5 stars first (before you rate anyone else).
INTENSITY = POWER/AREA = E^2/?0C
E^2 = 3.7 *10^-3*4*3.14*10^-7*3*10^8/4*3.14 *1.7*1.7*10^10^-6
E^2 = 3840
E = 61.96 V/m
B = E/c = 20.6 *10^-8 T
B) UB = B^2/2?0 = 20.6*20.6/2*4*3.14*10^-7 = 16.98 *10^7
Ue = 0.5 ?0 E^2 = 0.5*8.85*10^-12*61.96*61.96 = 16987*10^-12
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.