Find the wavelength (lambda), frequency (f), or medium speed (v) based on given

Question

Find the wavelength (lambda), frequency (f), or medium speed (v) based on given information. (use pi = 3.14) a. f = 10kHz, medium speed is 2 times 10^8 m/s b. lambda = 0.5m, medium speed is 2.5 times 10^8 m/s c. f = 10MHz, lambda = 30m Considering the channel that has transmission bit rate of 128kbps, if one image file, size of 1.5Mbytes, is transmitting over this channel, how long will it take in second to send this image file? Find data rate (R) or transmission time based on given information. a. A line has transmission rate of 5Mbps. What is the transmission time? b. A line has transmission tine of 0.25 mu s. What is the data rate? Assume that 1 symbol is transmitted over the 1 Mbps line and 1 symbol has 4 bits. Find the Transfer time and needed number of wires in each transfer mode a. Parallel transfer mode b. Serial transfer mode

Explanation / Answer

11-the formula is wavelength=medium speed / frequency
a- we have f=10Khz v=2*108
so wavelength = 2*108/10*1000 = 2*105 m

b-wavelength = 0.5 speed is 2.5*108
so frequency = 2*108 / 0.5 = 4*108 hz = 4*105 KHz

c-f= 10MHz wavelength=30m
medium speed = 10*106 * 30= 30* 107 m/s.

Q12- we have a transmission bit rate of 128 kbps and file size is 1.5 Mbytes time to transmit this file
file size= 1.5 Mbytes which is eqaul to 1.5*8*1024 kb = 1536 kb
time= size/transmission rate = 12288/128 = 96 sec.

14- we have 1 symbol of 4 bits abd is transmitted over a channel of 1Mbps
in parallel mode 8 bits are sent over frequent channels in one wire which increases transmission rate
so in parallel mode
we have only 4 bits to send and transmission channel is 1Mbps which is equal to 1000000 bits per second
so only one wire is needed to send the symbol and it will take 4*10^-6 seconds

in serial mode bits are send one after other through a single wire in a specific order and the order is very important.
in this 8 bits are sent at one time over a single wire
so in this mode again 1 wire is needed and it will take 4*10^-6 seconds.

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