A. If a thermodynamic system is taken along a path A along which 76.5 J flows in

Question

A. If a thermodynamic system is taken along a path A along which 76.5 J flows into the system and -45.2 J of work is done on the system, what is the change in internal energy, ?U?
?U: J
B. If the same system is taken along a second path B for which the internal energy, U, is constant, and -95.4 J of heat Q flows into the system, what is the work W done along that path?
W: J
C. If further this same system is taken along a third path C for which the internal energy, U, is constant, and -92.9 J of work W is done on the system, how much heat, Q, flows into the system?
Q: J

Explanation / Answer

1) Q = dU + W

Given Q = 76.5 and W =-45.2

dU =Q-w = 76.5 + 45.2

dU = 121.7 J

2) -95.4 = 121.7 + W

W = -217.1 J

3) Q = 121.7 - 92.9

Q= 28.8 J

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