A light, rigid rod of length l = 1.00 m joins two particles, with masses m 1 = 4

Question

A light, rigid rod of length l = 1.00 m joins two particles, with masses m1 = 4.00 kg and m2 = 3.00 kg, at its ends. The combination rotates in the xy plane about a pivot through the center of the rod (see figure below). Determine the angular momentum of the system about the origin when the speed of each particle is 6.40 m/s.

magnitude kg A light, rigid rod of length l = 1.00 m joins two particles, with masses m1 = 4.00 kg and m2 = 3.00 kg, at its ends. The combination rotates in the xy plane about a pivot through the center of the rod (see figure below). Determine the angular momentum of the system about the origin when the speed of each particle is 6.40 m/s.

Explanation / Answer

Both Angular momentum will be added

Angular momentum L=m1v1r1 sin@+m2v2r2 sin@

teta @=90 sin@=1 (@angle between v anf r)

so L=m1v1r1+m2v2r2=4.00*6.40*0.5+3.00*6.40*0.5=22.4 kg m/s

driectoin: perpendicularly outward to the paper page

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