An ideal monatomic gas expands isothermally from state A to state B . It then co
ID: 2251975 • Letter: A
Question
An ideal monatomic gas expands isothermally from state A to state B. It then cools at constant volume to state C. The gas is then compressed isobarically to D where it is then heated until it returns to state A
YOU SHOULD COME UP WITH THESE EXAXCT ANSWERS TO THESE QUESTIONS:
1.) What is the internal energy of the gas at point B? (Ans: 3x10^3 J)
2.) What is the pressure of the gas when it is in state B? (Ans: 5 atm)
3.) What is the temp. of the gas in state C? (Ans: -33 degrees C)
4.) What is the ratio of the internal energy of the gas in state C to that in state A? (Ans: 240/600)
5.) How much work is done on the gas as it is compressed isobarically from state C to state D? (Ans: 400J)
6.) What is the net amount of work done after one complete cycle? (Ans: 1000J)
An ideal monatomic gas expands isothermally from state A to state B. It then cools at constant volume to state C. The gas is then compressed isobarically to D where it is then heated until it returns to state A 1.) What is the internal energy of the gas at point B? (Ans: 3x10^3 J) What is the pressure of the gas when it is in state B? (Ans: 5 atm) What is the temp. of the gas in state C? (Ans: -33 degrees C) What is the ratio of the internal energy of the gas in state C to that in state A? (Ans: 240/600) How much work is done on the gas as it is compressed isobarically from state C to state D? (Ans: 400J) What is the net amount of work done after one complete cycle? (Ans: 1000J)Explanation / Answer
A to B is isothermal
so Ta = Tb = 327 C = 600 K
n = PaVa/RTa = 10*2/(0.0821*600) = 0.4
U = 1.5nRT
U = 1.5*0.4*8.314*600
U = 3 KJ
2)
isothermal
PaVa = PbVb
10*2 = Pb*4
Pb = 5 atm
3)
constant voliume
Pb/Tb = Pc/Tc
Tc = 2*(600/5) = 240 K = -33 C
4)
ratio of internal energy = Tc/Ta = 240/600
5)
Contant pressure process, Work done = P(Vd - Vc) = 2*(4 - 2) = 4 atm.L = 400 J
6)
Work done = nRTln2 + 400
= 0.4*8.314*600ln2 + 400 = 1000 J
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